200x^2-800x-960=0

Solution for 200x^2-800x-960=0 equation:

200x^2-800x-960=0

a = 200; b = -800; c = -960;
Δ = b2-4ac
Δ = -8002-4·200·(-960)
Δ = 1408000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1408000}=\sqrt{25600*55}=\sqrt{25600}*\sqrt{55}=160\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-800)-160\sqrt{55}}{2*200}=\frac{800-160\sqrt{55}}{400}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-800)+160\sqrt{55}}{2*200}=\frac{800+160\sqrt{55}}{400}
$